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                CATS                </h1>
                <p>时间限制：2s&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  空间限制：256MB</p>			</div>
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                                <h3>题目描述</h3><p><div><span style="font-size: medium">CATS(Counter and Two Stacks)是一门有一个counter和两个栈的语言。S1和S2是两个栈，初始时候每个栈中有无数个0，压栈和出栈的操作分别为&ldquo;PUSH&rdquo;和&ldquo;POP&rdquo;。&ldquo;ADD&rdquo;取出栈顶两个元素，并把和重新压栈。下程序中T1，T2分别表示S1，S2的栈顶元素。</span></div>
<div align="left"><span style="font-size: medium">COUNTER = X</span></div>
<div align="left"><span style="font-size: medium">WHILE COUNTER &gt; 0</span></div>
<div style="text-indent: 21pt" align="left"><span style="font-size: medium">S2 PUSH T1 &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; //把S1栈顶元素压入S2</span></div>
<div style="text-indent: 21pt" align="left"><span style="font-size: medium">S1 POP &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; //S1栈顶元素出栈</span></div>
<div style="text-indent: 21pt" align="left"><span style="font-size: medium">FLIP LAST BINARY BIT OF ALL NUMBERS IN S1&nbsp;//把S1中所有数的最后一位取反</span></div>
<div style="text-indent: 21pt" align="left"><span style="font-size: medium">IF T2 &gt; L</span></div>
<div style="margin: 0cm 0cm 0pt 21pt; text-indent: 21pt" align="left"><span style="font-size: medium">COUNTER = COUNTER - 1</span></div>
<div style="margin: 0cm 0cm 0pt 21pt; text-indent: 21pt" align="left"><span style="font-size: medium">IF COUNTER == 0 PRINT T2</span></div>
<div style="text-indent: 21pt" align="left"><span style="font-size: medium">ELSE</span></div>
<div style="margin: 0cm 0cm 0pt 21pt; text-indent: 21pt" align="left"><span style="font-size: medium">S2 PUSH N</span></div>
<div style="margin: 0cm 0cm 0pt 21pt; text-indent: 21pt" align="left"><span style="font-size: medium">S2 PUSH N</span></div>
<div style="margin: 0cm 0cm 0pt 21pt; text-indent: 21pt" align="left"><span style="font-size: medium">S2 ADD</span></div>
<div style="margin: 0cm 0cm 0pt 21pt; text-indent: 21pt" align="left"><span style="font-size: medium">S2 ADD</span></div>
<div style="margin: 0cm 0cm 0pt 21pt; text-indent: 21pt" align="left"><span style="font-size: medium">S1 PUSH T2</span></div>
<div style="margin: 0cm 0cm 0pt 21pt; text-indent: 21pt" align="left"><span style="font-size: medium">S1 PUSH T2</span></div>
<div style="margin: 0cm 0cm 0pt 21pt; text-indent: 21pt" align="left"><span style="font-size: medium">S2 POP</span></div>
<div style="margin: 0cm 0cm 0pt 21pt; text-indent: 21pt"><span style="font-size: medium">S2 POP</span></div>
<div><span style="font-size: medium">求该程序对于给定输入X,L,N的输出。</span></div></p><hr/><h3>输入格式</h3><p><div><span style="font-size: medium">第一行一个整数Q，接下来Q行每行有三个正整数分别为X,L和N，其中L不是N的倍数。</span></div></p><hr/><h3>输出格式</h3><p><div><span style="font-size: medium">输出共Q行，每行一个整数，为题目程序对于每组X,L和N的输出。</span></div></p><hr/><h3>样例输入</h3><pre>2
4 5 2
18 6 4</pre><hr/><h3>样例输出</h3><pre>8
9
样例输入输出解释：.
对于第一组X,L和N，以下为程序循环时栈S1和COUNTER的数值。为了表示方便，只显示栈S1最顶端的4个元素。每行最左边的数为S1的栈顶元素。
COUNTER: 4
S1: 0000...
COUNTER: 4
S1: 4411...
COUNTER: 4
S1: 8850...
COUNTER: 3
S1: 9411...
COUNTER: 2
S1: 5000...
COUNTER: 2
S1: 9911...
COUNTER: 1
S1: 8000...
在下个循环中，COUNTER= 0 所以输出为8。</pre><hr/><h3>提示</h3><p><p><span style="font-size: medium"><br />
&nbsp;<br />
数据规模：OJ中只有一组数据，Q=223100，X,N,L&lt;=2^60-1。</span></p></p><hr/><h3>题目来源</h3><p>By Hta</p>
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